Answer:The equation of the hyperbola is x²/60² - y²/11² = 1 ⇒ 1st answerStep-by-step explanation:* Lets study the equation of the hyperbola
- The standard form of the equation of a hyperbola with center (0 , 0) and transverse axis parallel to the x-axis is
x²/a² - y²/b² = 1
* Where:# the length of the transverse axis is 2a
# the coordinates of the vertices are (±a , 0)
# the length of the conjugate axis is 2b
# the coordinates of the co-vertices are (0 , ±b)
* Now from the graph- The center of the hyperbola is (0 , 0)- The vertices of the hyperbola are (-60 , 0) and (60 , 0)∴ a = ± 60∴ a² = 60²- The co-vertices of the hyperbola are (0 , -11) and (0 , 11)∴ b = ± 11∴ b² = 11²* Substitute the values of a² and b² in the form of the equation∴ x²/60² - y²/11² = 1* The equation of the hyperbola is x²/60² - y²/11² = 1